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Battle of Palo Alto
The Battle of Palo Alto was the first major battle of the Mexican–American War and was fought on May 8, 1846, on disputed ground five miles (8 km) from the modern-day city of Brownsville, Texas. A force of some 3,700 Mexican troops – a portion of the ''Army of The North'' – led by General Mariano Arista engaged a force of approximately 2,300 United States troops – the "''Army of Occupation''" led by General Zachary Taylor.〔
==Background==
Following the Thornton Affair, Arista on the last day in April, started crossing the Rio Grande at Longoreno with his main army, first with General Pedro de Ampudia's 1st Brigade and four guns.〔 Taylor prepared Fort Texas to withstand a siege while he moved most of his forces to protect his supply base at Fort Polk.〔 Fort Texas was garrisoned by Taylor with 500 men under Major Jacob Brown, including the 7th Infantry, Capt. Allen Lowd's four 18-pounders, and Lt. Braxton Bragg's field battery.〔
The battle began as a result of Mexican efforts to besiege Fort Texas on May 3, General Zachary Taylor, receiving supplies from Fort Polk on Point Isabel, heard the distant report of cannon fire.〔 Taylor started his return to Fort Texas on May 7 with 2,228 men plus his 200-wagon supply train.〔 General Arista immediately left his camp at the Tanques del Ramireno with his army with the intention of blocking Taylor.〔 Ampudia's brigade left the Fort Texas siege to join him.〔 Taylor's scouts sighted the Mexican force at noon on the 8th.〔
抄文引用元・出典: フリー百科事典『 ウィキペディア（Wikipedia）』
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